如何使用 DropDownList 的 SelectedIndexChanged 事件

  
本文介绍了如何使用 DropDownList 的 SelectedIndexChanged 事件的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

我的网络表单中有两个 DropDownList ，当我在第一个下拉列表中选择一个值时，我希望在第二个下拉列表中自动选择一个相关值.

I have two DropDownLists in my webform and when I select a value in the first dropdownlist, I would like a related value to be automatically selected in the second dropdownlist.

这是我目前拥有的:

    <table>   
        <tr>
            <td>
                <asp:Label ID="lbmanu" runat="server" Text="Furniture Manufacturer : 
                   "></asp:Label>
            </td>
            <td>
                <asp:DropDownList ID="ddmanu" runat="server" 
                    DataSourceID="Sql_fur_model_manu"    
                    DataTextField="manufacturer" DataValueField="manufacturer" 
                    onselectedindexchanged="ddmanu_SelectedIndexChanged">
                </asp:DropDownList>
                <asp:SqlDataSource ID="Sql_fur_model_manu" runat="server" 
                    ConnectionString="<%$ ConnectionStrings:conStr %>" 
                    SelectCommand="SELECT DISTINCT [manufacturer] FROM 
                     [furniture_manufacturer]">
                </asp:SqlDataSource>
            </td>
        </tr>
        <tr>
            <td>
                <asp:Label ID="lbtype" runat="server" Text="Furniture Type : 
                        "></asp:Label>
            </td>
            <td>
                <asp:DropDownList ID="ddtype" runat="server" AutoPostBack="True">
                   </asp:DropDownList>
            </td>
        </tr>
   </table>

背后的代码:

protected void ddmanu_SelectedIndexChanged(object sender, EventArgs e)
{
    string query = "select furniture from furniture_model where manufacturer='" + 
    ddmanu.SelectedValue.ToString() + "'";
    con.Open();
    cmd = new SqlCommand(query, con);
    DataTable dt = Select(query);
    cmd.ExecuteNonQuery();
    ddtype.DataSource = dt;
    ddtype.DataTextField = "manufacturer";
    ddtype.DataValueField = "furniture";
    ddtype.DataBind(); 
}

推荐答案

您应该将 AutoPostBack="true" 添加到 DropDownList1

You should add AutoPostBack="true" to DropDownList1

                <asp:DropDownList ID="ddmanu" runat="server" AutoPostBack="true"
                    DataSourceID="Sql_fur_model_manu"    
                    DataTextField="manufacturer" DataValueField="manufacturer" 
                    onselectedindexchanged="ddmanu_SelectedIndexChanged">
                </asp:DropDownList>

这篇关于如何使用 DropDownList 的 SelectedIndexChanged 事件的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持编程学习网！

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